OMG ANOTHER FUN AND EXCITING CLASS!!!!

Today we learned about the proness of  MOLE + WORD EQUTIONS OMG OMG OMG OMG. How hax is it? I have no idea but we all know because it is chemistry it have to be FUN! Right? Yep that’s my into for today and maybe next time when I am more creative I’ll write more or other stuff but today isn’t my creative day. OKAY ON TOPIC So what did we learn today? We learned about this thing called st-----metry yea something like that... After looking through an immense amount of books many scholars finally decided on Stoichiometry. So what does Stoichiometry mean??? Honestly I have no idea, but according to Wikipedia it is about the quantitative analysis of chemicals reactions and measuring the amount of elements and compounds involved in a reaction. So basically it means measuring chemicals in numbers and the number of elements and compound in an reaction. What does Stoichiomety help us find out? It find how many molecules of whatever element that is in a reaction that the reaction started with. So is this thing useful? Not really but its life so we have to learn it. Going back  a bit Stoichiometry can be separated into 2 Greek words stoichio which menas elements and metry is measurement.

Let’s start with an example

I have 90000 Cl and 1 Na what will I get?

9000Cl+1Na à NaCl + 8999Cl

Even though I have over 9 thousand of Cl I can only produce 1 NaCl because Na is the limiting factor.

First Q

C3H8+5O2à 4H2O +3CO2 how many grams of H2O will be produced if I burned 215G of C3H8?

First make everything into moles

215g C3H8 * mol C3H8/44GC3H8 = 4.89 mol C3H8

4.89 molC3H8 * 4mol H2O/1mol C3H8 = 19.5mol H2O

19.5mol H2O* 18gH2O/1mol H2O = 352g H2O

There done

More questions

the number of moles of carbon dioxide formed when 40.0 mol of oxygen is consumed in the burning of propane.

C₃H₈ + 5O₂ à 3CO₂ + 4H₂O

Molar Ratio 3 CO₂ / 5 O₂

40.0 mol O₂ x 3 mol CO₂ = 24.0 mol CO₂

                          5 mol O₂

A piece of iron (10moles) was dissolved in HCl. The reaction formed H₂ and FeCl₂ amount of FeCl2 formed and amound of HCl used.

  Fe + 2HCl = FeCl₂+H₂

10 mol Fe * 1mol FeCl2/1mol Fe  = 10mol FeCl2

HCl = 2(Fe) --> 20 moles of HCl was used.

Super typical chem teacher teaching on youtube.