Limiting and Excess Reactants

OK party people let MC JayLiu drop these beats on excess and limiting reactants

NO, that was NOT lame. In fact it's what all the fly kids by saying these days. Word

OKAY. So we see two terms from the title alone. Excess and limiting reactants? Let me put it in a way that most people can relate to.

Let's say for some unknown reason you want to make me a sandwich. Ingredients and supply? BREAD 10 pieces. SALAMI 489 slices. My sandwich consists of two pieces of bread with 267 slices of salami in between, no more, no less.

When we take a look at our bread supply, we see that we have to make five sandwiches. GREAT! Let's make 5 sandwiches.

HALT, EVIL DOER!

LOOK AGAIN, and you will see that we have a mere 489 slices of salami, enough to make 1 sandwich.

Therefore: only 1 sandwich can be made due to a LIMITING supply of salami, even though we have EXCESS bread. Also, JayLiu's 4th law of stoichiometry: One can never have EXCESS salami.

like this, without all that green crap

NOW, let's move away from the art of sandwich craft and move to ACTUAL Stoichiometry.

Eg. Butane burns in the presence of oxygen to form carbon dioxide and water. If 12.0g of butane reacted with 46.0g of oxygen, which reactant is excess/limiting and how many grams of CO2 will be produced?

STEP 1: WRITE THE EQUATION AND BALANCE

2 C4H10 + 13 O2 ------> 8 CO2 + 10 H2O

STEP 2: CONVERT ONE MASS INTO THE OTHER

(12.0g C4H10)(1 mol C4H10/58g C4H10)(13 mol O2/2 mol C4H10)(32g O2/1 mol O2) = 43.0g O2

since 43.0g < 46.0g, C4H10 is the limiting reactant by 3g

STEP 3: USING LIMITING REACTANT, FIND PRODUCT

(12.0g C4H10)(1 mol C4H10/58g C4H10)(4 mol CO2/1 mol C4H10)(44g CO2/1 mol CO2) = 36.4g CO2

Not the first video that appears when searching the query: "limiting and excess reactants".... the second